What are the solutions to the equation 12x^2=17x+5 ?

The solutions to the equation 12x^2=17x+5 are x= 5/3 ,x=-1/4

Find the zeros of 12x^2=17x+5

The zeros of 12x^2=17x+5 are x= 5/3 ,x=-1/4

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12 x^{2} = 17 x + 5

x = \frac{5}{3}, x = - \frac{1}{4}

Decimal Notation

x = 1.66666 \dots, x = - 0.25

Solution steps

12 x^{2} = 17 x + 5

Move

5

to the left side

12 x^{2} - 5 = 17 x

Move

17 x

to the left side

12 x^{2} - 5 - 17 x = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 17 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

(- 17)^{2} - 4 \cdot 12 (- 5) = 23

x_{1, 2} = \frac{- ( - 17 ) \pm 23}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 23}{2 \cdot 12}, x_{2} = \frac{- ( - 17 ) - 23}{2 \cdot 12}

x = \frac{- ( - 17 ) + 23}{2 \cdot 12} : \frac{5}{3}

x = \frac{- ( - 17 ) - 23}{2 \cdot 12} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - \frac{1}{4}

\frac{16 i ^{2}}{2 i}

(x - 2)^{4}

15 h^{2} - 17 h - 4

4 x^{2} + 36 x + 32

\frac{20 !}{14 ! 6 !}

What are the solutions to the equation 12x^2=17x+5 ?
The solutions to the equation 12x^2=17x+5 are x= 5/3 ,x=-1/4
Find the zeros of 12x^2=17x+5
The zeros of 12x^2=17x+5 are x= 5/3 ,x=-1/4