What are the solutions to the equation 0=x^2+9x-36 ?

The solutions to the equation 0=x^2+9x-36 are x=3,x=-12

Find the zeros of 0=x^2+9x-36

The zeros of 0=x^2+9x-36 are x=3,x=-12

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0 = x^{2} + 9 x - 36

x = 3, x = - 12

Solution steps

0 = x^{2} + 9 x - 36

Switch sides

x^{2} + 9 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 36) = 15

x_{1, 2} = \frac{- 9 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 15}{2 \cdot 1}, x_{2} = \frac{- 9 - 15}{2 \cdot 1}

x = \frac{- 9 + 15}{2 \cdot 1} : 3

x = \frac{- 9 - 15}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 3, x = - 12

(- 3 x^{3} y^{5})^{3}

2 x^{2} + x y - y^{2}

- x < 4

1 + \frac{8}{5}

- 3 x^{2} + 9 x + 12 = 0

What are the solutions to the equation 0=x^2+9x-36 ?
The solutions to the equation 0=x^2+9x-36 are x=3,x=-12
Find the zeros of 0=x^2+9x-36
The zeros of 0=x^2+9x-36 are x=3,x=-12