What are the solutions to the equation x^2+7x=0 ?

The solutions to the equation x^2+7x=0 are x=0,x=-7

Find the zeros of x^2+7x=0

The zeros of x^2+7x=0 are x=0,x=-7

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x^{2} + 7 x = 0

x = 0, x = - 7

Solution steps

x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 \cdot 1}, x_{2} = \frac{- 7 - 7}{2 \cdot 1}

x = \frac{- 7 + 7}{2 \cdot 1} : 0

x = \frac{- 7 - 7}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

15 - 2 w - 2 = 2 (w - 15) - 1

(\frac{3 x ^{2}}{7})^{2}

5 x^{2} + x - 1 < 0

- \frac{\frac{51}{52}}{- \frac{17}{26}}

7 - 3 (2) = 3 + c (2)

What are the solutions to the equation x^2+7x=0 ?
The solutions to the equation x^2+7x=0 are x=0,x=-7
Find the zeros of x^2+7x=0
The zeros of x^2+7x=0 are x=0,x=-7