What is the answer to (2x-4)/7 =(x-1)/5 ?

The answer to (2x-4)/7 =(x-1)/5 is x= 13/3

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(2x-4)/7 =(x-1)/5

\frac{2 x - 4}{7} = \frac{x - 1}{5}

x = \frac{13}{3}

Decimal Notation

x = 4.33333 \dots

Solution steps

\frac{2 x - 4}{7} = \frac{x - 1}{5}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 x - 4) \cdot 5 = 7 (x - 1)

Expand

(2 x - 4) \cdot 5 : 10 x - 20

Expand

7 (x - 1) : 7 x - 7

10 x - 20 = 7 x - 7

Move

20

to the right side

10 x = 7 x + 13

Move

7 x

to the left side

3 x = 13

Divide both sides by

3

x = \frac{13}{3}

9 m^{2} - 16

x^{3} < 64 x

6 x - 3 = 21

2 x^{2} + 6 x + 2 = 0

What is the answer to (2x-4)/7 =(x-1)/5 ?
The answer to (2x-4)/7 =(x-1)/5 is x= 13/3
Solve for x: (2x-4)/7 =(x-1)/5
The solution is x= 13/3