What are the solutions to the equation 4y^2=48 ?

The solutions to the equation 4y^2=48 are y=2sqrt(3),y=-2sqrt(3)

Find the zeros of 4y^2=48

The zeros of 4y^2=48 are y=2sqrt(3),y=-2sqrt(3)

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4 y^{2} = 48

y = 23, y = - 23

Decimal Notation

y = 3.46410 \dots, y = - 3.46410 \dots

Solution steps

4 y^{2} = 48

Divide both sides by

4

y^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 12, y = - 12

12 = 23

- 12 = - 23

y = 23, y = - 23

8 (- 3) - 2 (- 6) < - 12

k^{2} - 4 k - 12

x^{2} - 6 x + 5 = 5 - 2 x

x^{2} + 5 x \geq - 6

- 12 x + 11 \leq - 11 (x - 1)

What are the solutions to the equation 4y^2=48 ?
The solutions to the equation 4y^2=48 are y=2sqrt(3),y=-2sqrt(3)
Find the zeros of 4y^2=48
The zeros of 4y^2=48 are y=2sqrt(3),y=-2sqrt(3)