What are the solutions to the equation 50=126t-16t^2 ?

The solutions to the equation 50=126t-16t^2 are t=(63-sqrt(3169))/(16),t=(63+sqrt(3169))/(16)

Find the zeros of 50=126t-16t^2

The zeros of 50=126t-16t^2 are t=(63-sqrt(3169))/(16),t=(63+sqrt(3169))/(16)

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50 = 126 t - 16 t^{2}

t = \frac{63 - 3169}{16}, t = \frac{63 + 3169}{16}

Decimal Notation

t = 0.41913 \dots, t = 7.45586 \dots

Solution steps

50 = 126 t - 16 t^{2}

Switch sides

126 t - 16 t^{2} = 50

Move

50

to the left side

126 t - 16 t^{2} - 50 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 126 t - 50 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 126 \pm 12 6 ^{2} - 4 ( - 16 ) ( - 50 )}{2 ( - 16 )}

12 6^{2} - 4 (- 16) (- 50) = 23169

t_{1, 2} = \frac{- 126 \pm 2 3169}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 126 + 2 3169}{2 ( - 16 )}, t_{2} = \frac{- 126 - 2 3169}{2 ( - 16 )}

t = \frac{- 126 + 2 3169}{2 ( - 16 )} : \frac{63 - 3169}{16}

t = \frac{- 126 - 2 3169}{2 ( - 16 )} : \frac{63 + 3169}{16}

The solutions to the quadratic equation are:

t = \frac{63 - 3169}{16}, t = \frac{63 + 3169}{16}

10 - 3 x^{2} > x^{2} + 10 - x

C = \frac{5}{9} (50 - 32)

(4 x)^{2}

12 (- \frac{7}{3}) - 4 (- \frac{7}{3}) + 14

3 x + 2 < 14

What are the solutions to the equation 50=126t-16t^2 ?
The solutions to the equation 50=126t-16t^2 are t=(63-sqrt(3169))/(16),t=(63+sqrt(3169))/(16)
Find the zeros of 50=126t-16t^2
The zeros of 50=126t-16t^2 are t=(63-sqrt(3169))/(16),t=(63+sqrt(3169))/(16)