What are the solutions to the equation (x-9)(x+3)=0 ?

The solutions to the equation (x-9)(x+3)=0 are x=9,x=-3

Find the zeros of (x-9)(x+3)=0

The zeros of (x-9)(x+3)=0 are x=9,x=-3

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(x - 9) (x + 3) = 0

x = 9, x = - 3

Solution steps

(x - 9) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or x + 3 = 0

Solve

x - 9 = 0 : x = 9

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 9, x = - 3

(- 25) (- 36)

- 6 = a (5 - 2)^{2} - 3

5 a^{2} - 3 a - 2

- \frac{3}{2} (2)^{- 1}

ab + 10 a + 2 b + 20

What are the solutions to the equation (x-9)(x+3)=0 ?
The solutions to the equation (x-9)(x+3)=0 are x=9,x=-3
Find the zeros of (x-9)(x+3)=0
The zeros of (x-9)(x+3)=0 are x=9,x=-3