What are the solutions to the equation a^2-a-72=0 ?

The solutions to the equation a^2-a-72=0 are a=9,a=-8

Find the zeros of a^2-a-72=0

The zeros of a^2-a-72=0 are a=9,a=-8

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a^{2} - a - 72 = 0

a = 9, a = - 8

Solution steps

a^{2} - a - 72 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 72) = 17

a_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 1}

a = \frac{- ( - 1 ) + 17}{2 \cdot 1} : 9

a = \frac{- ( - 1 ) - 17}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

a = 9, a = - 8

x + 3 = 2 x + 1

t + 1 < 3

- 5 + 8 a = - 4 + 7 a

\frac{2}{3} x = 10

2 ∣ 6 x + 5 ∣ - 1 = 25

What are the solutions to the equation a^2-a-72=0 ?
The solutions to the equation a^2-a-72=0 are a=9,a=-8
Find the zeros of a^2-a-72=0
The zeros of a^2-a-72=0 are a=9,a=-8