What are the solutions to the equation 3x^2-6x-11=0 ?

The solutions to the equation 3x^2-6x-11=0 are x=(3+sqrt(42))/3 ,x=(3-sqrt(42))/3

Find the zeros of 3x^2-6x-11=0

The zeros of 3x^2-6x-11=0 are x=(3+sqrt(42))/3 ,x=(3-sqrt(42))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 6 x - 11 = 0

x = \frac{3 + 42}{3}, x = \frac{3 - 42}{3}

Decimal Notation

x = 3.16024 \dots, x = - 1.16024 \dots

Solution steps

3 x^{2} - 6 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 11 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 11) = 242

x_{1, 2} = \frac{- ( - 6 ) \pm 2 42}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 42}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 42}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 42}{2 \cdot 3} : \frac{3 + 42}{3}

x = \frac{- ( - 6 ) - 2 42}{2 \cdot 3} : \frac{3 - 42}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 42}{3}, x = \frac{3 - 42}{3}

\frac{10 - 4 x}{2 x - 5} \geq 4 x - 1

x^{2} + 4 x + 21 = 42

9 (3 x + 9) + (x + 3) = 14

\frac{\frac{2 x + y}{36}}{\frac{36 + 36 x - 7 x ^{2}}{288}}

- \frac{11}{2 ( - 3 + 4 ) ^{2}}

What are the solutions to the equation 3x^2-6x-11=0 ?
The solutions to the equation 3x^2-6x-11=0 are x=(3+sqrt(42))/3 ,x=(3-sqrt(42))/3
Find the zeros of 3x^2-6x-11=0
The zeros of 3x^2-6x-11=0 are x=(3+sqrt(42))/3 ,x=(3-sqrt(42))/3