What are the solutions to the equation x^2+5x+9=0 ?

The solutions to the equation x^2+5x+9=0 are x=-5/2+i(sqrt(11))/2 ,x=-5/2-i(sqrt(11))/2

Find the zeros of x^2+5x+9=0

The zeros of x^2+5x+9=0 are x=-5/2+i(sqrt(11))/2 ,x=-5/2-i(sqrt(11))/2

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x^{2} + 5 x + 9 = 0

x = - \frac{5}{2} + i \frac{11}{2}, x = - \frac{5}{2} - i \frac{11}{2}

Solution steps

x^{2} + 5 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 9 : 11 i

x_{1, 2} = \frac{- 5 \pm 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 11 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 11 i}{2 \cdot 1}

x = \frac{- 5 + 11 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{11}{2}

x = \frac{- 5 - 11 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{11}{2}, x = - \frac{5}{2} - i \frac{11}{2}

3 x^{3} - 6 x^{2} - 45 x

lo g_{4} (2 x + 5) \leq lo g_{4} (4 x - 3)

\frac{1}{4 ^{- 1}}

∣ x + 3 ∣ \leq 2

5 = \frac{1}{3} (2 x + 12)

What are the solutions to the equation x^2+5x+9=0 ?
The solutions to the equation x^2+5x+9=0 are x=-5/2+i(sqrt(11))/2 ,x=-5/2-i(sqrt(11))/2
Find the zeros of x^2+5x+9=0
The zeros of x^2+5x+9=0 are x=-5/2+i(sqrt(11))/2 ,x=-5/2-i(sqrt(11))/2