What is ((z^2w^{-1})^3)/((z^3w^2)^2) ?

The solution to ((z^2w^{-1})^3)/((z^3w^2)^2) is 1/(w^7)

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simplify ((z^2w^{-1})^3)/((z^3w^2)^2)

simplify

\frac{( z ^{2} w ^{- 1} ) ^{3}}{( z ^{3} w ^{2} ) ^{2}}

\frac{1}{w ^{7}}

Solution steps

\frac{( z ^{2} w ^{- 1} ) ^{3}}{( z ^{3} w ^{2} ) ^{2}}

Simplify

(z^{2} w^{- 1})^{3} : z^{6} \frac{1}{w ^{3}}

= \frac{z ^{6} \frac{1}{w ^{3}}}{( z ^{3} w ^{2} ) ^{2}}

Simplify

(z^{3} w^{2})^{2} : z^{6} w^{4}

= \frac{z ^{6} \frac{1}{w ^{3}}}{z ^{6} w ^{4}}

Cancel the common factor:

z^{6}

= \frac{\frac{1}{w ^{3}}}{w ^{4}}

Simplify

\frac{\frac{1}{w ^{3}}}{w ^{4}} : \frac{1}{w ^{7}}

= \frac{1}{w ^{7}}

(\frac{1}{x} + \frac{1}{y})^{- 1}

1 - (\frac{1}{4})^{4}

21 a^{2} c^{3} - 35 a c^{2} + 7 a^{2} c

- 6 x < 42

5 (x + 9)^{2} - 16 = - 6

What is ((z^2w^{-1})^3)/((z^3w^2)^2) ?
The solution to ((z^2w^{-1})^3)/((z^3w^2)^2) is 1/(w^7)