What are the solutions to the equation 96=(2x+4)x ?

The solutions to the equation 96=(2x+4)x are x=6,x=-8

Find the zeros of 96=(2x+4)x

The zeros of 96=(2x+4)x are x=6,x=-8

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96 = (2 x + 4) x

x = 6, x = - 8

Solution steps

96 = (2 x + 4) x

Expand

(2 x + 4) x : 2 x^{2} + 4 x

96 = 2 x^{2} + 4 x

Switch sides

2 x^{2} + 4 x = 96

Move

96

to the left side

2 x^{2} + 4 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 96 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 96) = 28

x_{1, 2} = \frac{- 4 \pm 28}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 28}{2 \cdot 2}, x_{2} = \frac{- 4 - 28}{2 \cdot 2}

x = \frac{- 4 + 28}{2 \cdot 2} : 6

x = \frac{- 4 - 28}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = 6, x = - 8

x^{2} + 10 x + 24 \geq 0

\frac{1}{4} \cdot 25

x^{2} - \frac{4}{5} x = \frac{16}{25}

(2 x + 1)^{2} = 25

3 ∣ x - 3 ∣ + 6 > 12

What are the solutions to the equation 96=(2x+4)x ?
The solutions to the equation 96=(2x+4)x are x=6,x=-8
Find the zeros of 96=(2x+4)x
The zeros of 96=(2x+4)x are x=6,x=-8