What are the solutions to the equation 3x^2+12x-6=0 ?

The solutions to the equation 3x^2+12x-6=0 are x=-2+sqrt(6),x=-2-sqrt(6)

Find the zeros of 3x^2+12x-6=0

The zeros of 3x^2+12x-6=0 are x=-2+sqrt(6),x=-2-sqrt(6)

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3 x^{2} + 12 x - 6 = 0

x = - 2 + 6, x = - 2 - 6

Decimal Notation

x = 0.44948 \dots, x = - 4.44948 \dots

Solution steps

3 x^{2} + 12 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 6) = 66

x_{1, 2} = \frac{- 12 \pm 6 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 6 6}{2 \cdot 3}, x_{2} = \frac{- 12 - 6 6}{2 \cdot 3}

x = \frac{- 12 + 6 6}{2 \cdot 3} : - 2 + 6

x = \frac{- 12 - 6 6}{2 \cdot 3} : - 2 - 6

The solutions to the quadratic equation are:

x = - 2 + 6, x = - 2 - 6

x^{5} + 6 x^{4} y + 9 x^{3} y^{2} + x^{2} y^{3} + 6 x y^{4} + 9 y^{5}

\frac{11 + 3}{11 - 3}

x^{4} + 16 x^{2}

x^{3} - 4 x^{2} + 5 x

2 x^{2} + 8 x + 77 = 0

What are the solutions to the equation 3x^2+12x-6=0 ?
The solutions to the equation 3x^2+12x-6=0 are x=-2+sqrt(6),x=-2-sqrt(6)
Find the zeros of 3x^2+12x-6=0
The zeros of 3x^2+12x-6=0 are x=-2+sqrt(6),x=-2-sqrt(6)