What are the solutions to the equation x^2+5x+2=0 ?

The solutions to the equation x^2+5x+2=0 are x=(-5+sqrt(17))/2 ,x=(-5-sqrt(17))/2

Find the zeros of x^2+5x+2=0

The zeros of x^2+5x+2=0 are x=(-5+sqrt(17))/2 ,x=(-5-sqrt(17))/2

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x^{2} + 5 x + 2 = 0

x = \frac{- 5 + 17}{2}, x = \frac{- 5 - 17}{2}

Decimal Notation

x = - 0.43844 \dots, x = - 4.56155 \dots

Solution steps

x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 2 = 17

x_{1, 2} = \frac{- 5 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 17}{2 \cdot 1}, x_{2} = \frac{- 5 - 17}{2 \cdot 1}

x = \frac{- 5 + 17}{2 \cdot 1} : \frac{- 5 + 17}{2}

x = \frac{- 5 - 17}{2 \cdot 1} : \frac{- 5 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 17}{2}, x = \frac{- 5 - 17}{2}

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- 0.04 X^{2} + 0.64 X + 15 = 0

\frac{6 x ^{2} y ^{3}}{( - 4 x ^{4} y ) ( - 3 x ^{3} y ^{2} )}

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What are the solutions to the equation x^2+5x+2=0 ?
The solutions to the equation x^2+5x+2=0 are x=(-5+sqrt(17))/2 ,x=(-5-sqrt(17))/2
Find the zeros of x^2+5x+2=0
The zeros of x^2+5x+2=0 are x=(-5+sqrt(17))/2 ,x=(-5-sqrt(17))/2