What are the solutions to the equation x^2-5x=14 ?

The solutions to the equation x^2-5x=14 are x=7,x=-2

Find the zeros of x^2-5x=14

The zeros of x^2-5x=14 are x=7,x=-2

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x^{2} - 5 x = 14

x = 7, x = - 2

Solution steps

x^{2} - 5 x = 14

Move

14

to the left side

x^{2} - 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

x = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

x = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 7, x = - 2

3^{\frac{7}{3}}

(2 x + 1)^{2} - (3 x - 2)^{2} = 5 x (2 - x)

4 x - 29 = 3 x - 2

\frac{2}{3} x y^{2} + 2 x - \frac{1}{3} x y^{2} + \frac{2}{3} x^{2} y - 5 x

What are the solutions to the equation x^2-5x=14 ?
The solutions to the equation x^2-5x=14 are x=7,x=-2
Find the zeros of x^2-5x=14
The zeros of x^2-5x=14 are x=7,x=-2