What are the solutions to the equation (3x-2)^2-4=9x-6 ?

The solutions to the equation (3x-2)^2-4=9x-6 are x=2,x= 1/3

Find the zeros of (3x-2)^2-4=9x-6

The zeros of (3x-2)^2-4=9x-6 are x=2,x= 1/3

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(3 x - 2)^{2} - 4 = 9 x - 6

x = 2, x = \frac{1}{3}

Decimal Notation

x = 2, x = 0.33333 \dots

Solution steps

(3 x - 2)^{2} - 4 = 9 x - 6

Expand

(3 x - 2)^{2} - 4 : 9 x^{2} - 12 x

9 x^{2} - 12 x = 9 x - 6

Move

6

to the left side

9 x^{2} - 12 x + 6 = 9 x

Move

9 x

to the left side

9 x^{2} - 21 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 9 \cdot 6}{2 \cdot 9}

(- 21)^{2} - 4 \cdot 9 \cdot 6 = 15

x_{1, 2} = \frac{- ( - 21 ) \pm 15}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 15}{2 \cdot 9}, x_{2} = \frac{- ( - 21 ) - 15}{2 \cdot 9}

x = \frac{- ( - 21 ) + 15}{2 \cdot 9} : 2

x = \frac{- ( - 21 ) - 15}{2 \cdot 9} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{3}

\frac{6 π}{2}

(\frac{5}{8})^{2}

2^{2} + 1^{2}

(2 a)^{3}

13 (a - 1) + 52 (1 - a)^{3}

What are the solutions to the equation (3x-2)^2-4=9x-6 ?
The solutions to the equation (3x-2)^2-4=9x-6 are x=2,x= 1/3
Find the zeros of (3x-2)^2-4=9x-6
The zeros of (3x-2)^2-4=9x-6 are x=2,x= 1/3