What are the solutions to the equation 6x^2+7x+2=0 ?

The solutions to the equation 6x^2+7x+2=0 are x=-1/2 ,x=-2/3

Find the zeros of 6x^2+7x+2=0

The zeros of 6x^2+7x+2=0 are x=-1/2 ,x=-2/3

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6 x^{2} + 7 x + 2 = 0

x = - \frac{1}{2}, x = - \frac{2}{3}

Decimal Notation

x = - 0.5, x = - 0.66666 \dots

Solution steps

6 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

7^{2} - 4 \cdot 6 \cdot 2 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 6}, x_{2} = \frac{- 7 - 1}{2 \cdot 6}

x = \frac{- 7 + 1}{2 \cdot 6} : - \frac{1}{2}

x = \frac{- 7 - 1}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{2}{3}

x^{- \frac{1}{4}}

(A^{1 + \frac{x}{y}})^{\frac{y}{x + y}}

lo g_{7} (49)

- 4 (x + 4) < 4

\frac{( x + 7 ) ( x - 3 )}{( x - 5 ) ^{2}} > 0

What are the solutions to the equation 6x^2+7x+2=0 ?
The solutions to the equation 6x^2+7x+2=0 are x=-1/2 ,x=-2/3
Find the zeros of 6x^2+7x+2=0
The zeros of 6x^2+7x+2=0 are x=-1/2 ,x=-2/3