What are the solutions to the equation x^2+x-7=-7 ?

The solutions to the equation x^2+x-7=-7 are x=0,x=-1

Find the zeros of x^2+x-7=-7

The zeros of x^2+x-7=-7 are x=0,x=-1

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x^{2} + x - 7 = - 7

x = 0, x = - 1

Solution steps

x^{2} + x - 7 = - 7

Move

7

to the left side

x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 1}, x_{2} = \frac{- 1 - 1}{2 \cdot 1}

x = \frac{- 1 + 1}{2 \cdot 1} : 0

x = \frac{- 1 - 1}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

y^{2} + 2 y - 8 = 0

6 x + 35 = - 6 x + 35

14 \cdot \frac{2}{3}

\frac{1}{8} + \frac{1}{4} + \frac{1}{2}

(\frac{6}{n})^{- 2}

What are the solutions to the equation x^2+x-7=-7 ?
The solutions to the equation x^2+x-7=-7 are x=0,x=-1
Find the zeros of x^2+x-7=-7
The zeros of x^2+x-7=-7 are x=0,x=-1