What are the solutions to the equation 3s^2+10s+6=-30 ?

The solutions to the equation 3s^2+10s+6=-30 are s=-5/3+i(sqrt(83))/3 ,s=-5/3-i(sqrt(83))/3

Find the zeros of 3s^2+10s+6=-30

The zeros of 3s^2+10s+6=-30 are s=-5/3+i(sqrt(83))/3 ,s=-5/3-i(sqrt(83))/3

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3 s^{2} + 10 s + 6 = - 30

s = - \frac{5}{3} + i \frac{83}{3}, s = - \frac{5}{3} - i \frac{83}{3}

Solution steps

3 s^{2} + 10 s + 6 = - 30

Move

30

to the left side

3 s^{2} + 10 s + 36 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 \cdot 36}{2 \cdot 3}

Simplify

1 0^{2} - 4 \cdot 3 \cdot 36 : 283 i

s_{1, 2} = \frac{- 10 \pm 2 83 i}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- 10 + 2 83 i}{2 \cdot 3}, s_{2} = \frac{- 10 - 2 83 i}{2 \cdot 3}

s = \frac{- 10 + 2 83 i}{2 \cdot 3} : - \frac{5}{3} + i \frac{83}{3}

s = \frac{- 10 - 2 83 i}{2 \cdot 3} : - \frac{5}{3} - i \frac{83}{3}

The solutions to the quadratic equation are:

s = - \frac{5}{3} + i \frac{83}{3}, s = - \frac{5}{3} - i \frac{83}{3}

\frac{4 x}{x + 2} + \frac{5}{x + 1} < 0

- 3 k - k + 10 = 2

x^{8} - 81

\frac{5}{2} (4)

x + 1 \leq 9

What are the solutions to the equation 3s^2+10s+6=-30 ?
The solutions to the equation 3s^2+10s+6=-30 are s=-5/3+i(sqrt(83))/3 ,s=-5/3-i(sqrt(83))/3
Find the zeros of 3s^2+10s+6=-30
The zeros of 3s^2+10s+6=-30 are s=-5/3+i(sqrt(83))/3 ,s=-5/3-i(sqrt(83))/3