What are the solutions to the equation 7x^2-2x-1=0 ?

The solutions to the equation 7x^2-2x-1=0 are x=(1+2sqrt(2))/7 ,x=(1-2sqrt(2))/7

Find the zeros of 7x^2-2x-1=0

The zeros of 7x^2-2x-1=0 are x=(1+2sqrt(2))/7 ,x=(1-2sqrt(2))/7

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7 x^{2} - 2 x - 1 = 0

x = \frac{1 + 2 2}{7}, x = \frac{1 - 2 2}{7}

Decimal Notation

x = 0.54691 \dots, x = - 0.26120 \dots

Solution steps

7 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 1) = 42

x_{1, 2} = \frac{- ( - 2 ) \pm 4 2}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 2}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 4 2}{2 \cdot 7}

x = \frac{- ( - 2 ) + 4 2}{2 \cdot 7} : \frac{1 + 2 2}{7}

x = \frac{- ( - 2 ) - 4 2}{2 \cdot 7} : \frac{1 - 2 2}{7}

The solutions to the quadratic equation are:

x = \frac{1 + 2 2}{7}, x = \frac{1 - 2 2}{7}

8 x^{2} - 26 x + 6

x^{2} - 7 x \geq 0

t^{2} + 10 t + 16

a^{2} x^{6} - a^{2} y^{6}

9 m^{2} - 169

What are the solutions to the equation 7x^2-2x-1=0 ?
The solutions to the equation 7x^2-2x-1=0 are x=(1+2sqrt(2))/7 ,x=(1-2sqrt(2))/7
Find the zeros of 7x^2-2x-1=0
The zeros of 7x^2-2x-1=0 are x=(1+2sqrt(2))/7 ,x=(1-2sqrt(2))/7