What is factor t^2+8t-48 ?

The solution to factor t^2+8t-48 is (t-4)(t+12)

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factor t^2+8t-48

factor

t^{2} + 8 t - 48

(t - 4) (t + 12)

Solution steps

t^{2} + 8 t - 48

Break the expression into groups

= (t^{2} - 4 t) + (12 t - 48)

Factor out

t

from

t^{2} - 4 t : t (t - 4)

Factor out

12

from

12 t - 48 : 12 (t - 4)

= t (t - 4) + 12 (t - 4)

Factor out common term

t - 4

= (t - 4) (t + 12)

\frac{x}{7} - 3 \geq 8

4 \leq ∣ w - 6 ∣

1.5 - 2.5 x \leq 4.5

1.5 b + 9 = 11

\frac{12 c}{( 4 c ^{3} ) ^{2}}