What are the solutions to the equation (5x+2)^2+15x+6=0 ?

The solutions to the equation (5x+2)^2+15x+6=0 are x=-2/5 ,x=-1

Find the zeros of (5x+2)^2+15x+6=0

The zeros of (5x+2)^2+15x+6=0 are x=-2/5 ,x=-1

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(5 x + 2)^{2} + 15 x + 6 = 0

x = - \frac{2}{5}, x = - 1

Decimal Notation

x = - 0.4, x = - 1

Solution steps

(5 x + 2)^{2} + 15 x + 6 = 0

Expand

(5 x + 2)^{2} + 15 x + 6 : 25 x^{2} + 35 x + 10

25 x^{2} + 35 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 25 \cdot 10}{2 \cdot 25}

3 5^{2} - 4 \cdot 25 \cdot 10 = 15

x_{1, 2} = \frac{- 35 \pm 15}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 35 + 15}{2 \cdot 25}, x_{2} = \frac{- 35 - 15}{2 \cdot 25}

x = \frac{- 35 + 15}{2 \cdot 25} : - \frac{2}{5}

x = \frac{- 35 - 15}{2 \cdot 25} : - 1

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - 1

2 d^{2} + 7 d + 5

9 = 4 a + 13

- 5 x + 3 > - 17

lo g_{6} (6^{4})

(2 x - 5)^{2} = 0

What are the solutions to the equation (5x+2)^2+15x+6=0 ?
The solutions to the equation (5x+2)^2+15x+6=0 are x=-2/5 ,x=-1
Find the zeros of (5x+2)^2+15x+6=0
The zeros of (5x+2)^2+15x+6=0 are x=-2/5 ,x=-1