What are the solutions to the equation 5(x-4)^2=-5 ?

The solutions to the equation 5(x-4)^2=-5 are x=i+4,x=-i+4

Find the zeros of 5(x-4)^2=-5

The zeros of 5(x-4)^2=-5 are x=i+4,x=-i+4

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5 (x - 4)^{2} = - 5

x = i + 4, x = - i + 4

Solution steps

5 (x - 4)^{2} = - 5

Divide both sides by

5

(x - 4)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 1 : x = i + 4

Solve

x - 4 = - - 1 : x = - i + 4

The solutions to the quadratic equation are:

x = i + 4, x = - i + 4

- x = - 1

2 = - \frac{4}{3} a

(36 x)^{\frac{1}{2}} (49 x)^{\frac{1}{2}}

2 x + 5 = 3 + 2 (x + 1)

3 q^{2} + q - 2

What are the solutions to the equation 5(x-4)^2=-5 ?
The solutions to the equation 5(x-4)^2=-5 are x=i+4,x=-i+4
Find the zeros of 5(x-4)^2=-5
The zeros of 5(x-4)^2=-5 are x=i+4,x=-i+4