What are the solutions to the equation 5w^2=-26w-5 ?

The solutions to the equation 5w^2=-26w-5 are w=-1/5 ,w=-5

Find the zeros of 5w^2=-26w-5

The zeros of 5w^2=-26w-5 are w=-1/5 ,w=-5

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5 w^{2} = - 26 w - 5

w = - \frac{1}{5}, w = - 5

Solution steps

5 w^{2} = - 26 w - 5

Move

5

to the left side

5 w^{2} + 5 = - 26 w

Move

26 w

to the left side

5 w^{2} + 5 + 26 w = 0

Write in the standard form

a x^{2} + b x + c = 0

5 w^{2} + 26 w + 5 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

2 6^{2} - 4 \cdot 5 \cdot 5 = 24

w_{1, 2} = \frac{- 26 \pm 24}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- 26 + 24}{2 \cdot 5}, w_{2} = \frac{- 26 - 24}{2 \cdot 5}

w = \frac{- 26 + 24}{2 \cdot 5} : - \frac{1}{5}

w = \frac{- 26 - 24}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

w = - \frac{1}{5}, w = - 5

n^{3} + 2 n^{2} - 4 n - 8

\frac{x + 5}{3} = 2

∣ 9 x - 36 ∣ = 0

(x - 7)^{2} = 64

2 x - 10

What are the solutions to the equation 5w^2=-26w-5 ?
The solutions to the equation 5w^2=-26w-5 are w=-1/5 ,w=-5
Find the zeros of 5w^2=-26w-5
The zeros of 5w^2=-26w-5 are w=-1/5 ,w=-5