What is factor x^4-2x^3-12x^2+40x-32 ?

The solution to factor x^4-2x^3-12x^2+40x-32 is (x-2)^3(x+4)

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factor x^4-2x^3-12x^2+40x-32

factor

x^{4} - 2 x^{3} - 12 x^{2} + 40 x - 32

(x - 2)^{3} (x + 4)

Solution steps

x^{4} - 2 x^{3} - 12 x^{2} + 40 x - 32

Use the rational root theorem

= (x - 2) \frac{x ^{4} - 2 x ^{3} - 12 x ^{2} + 40 x - 32}{x - 2}

\frac{x ^{4} - 2 x ^{3} - 12 x ^{2} + 40 x - 32}{x - 2} = x^{3} - 12 x + 16

= (x - 2) (x^{3} - 12 x + 16)

Factor

x^{3} - 12 x + 16 : (x - 2) (x - 2) (x + 4)

= (x - 2) (x - 2) (x - 2) (x + 4)

Apply exponent rule:

aaa = a^{3}

(x - 2) (x - 2) (x - 2) = (x - 2)^{3}

= (x - 2)^{3} (x + 4)

5 x^{2} + 6 x + 1.8 = 0

16 n^{2} - 10 n - 5 = 6 n

4 (3.5) - 2 > 3 (3.5) + 1

8 p^{2} + 8 p

x^{4} + 5 x^{3} + 4 x + 20

What is factor x^4-2x^3-12x^2+40x-32 ?
The solution to factor x^4-2x^3-12x^2+40x-32 is (x-2)^3(x+4)