What are the solutions to the equation r^2-8r=0 ?

The solutions to the equation r^2-8r=0 are r=8,r=0

Find the zeros of r^2-8r=0

The zeros of r^2-8r=0 are r=8,r=0

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r^{2} - 8 r = 0

r = 8, r = 0

Solution steps

r^{2} - 8 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

r_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

r = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

r = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

r = 8, r = 0

(11 x^{\frac{1}{2} + 2}) 2 x

5445 + 0.345 - 45 \cdot 4997 (674 \cdot 447) = 0 \cdot 5 + 69

- 2 x^{2} - 4 x + 3 = 0

8^{2} + 6^{2} = c^{2}

7^{\frac{1}{5}} \cdot 4 9^{\frac{7}{5}}

What are the solutions to the equation r^2-8r=0 ?
The solutions to the equation r^2-8r=0 are r=8,r=0
Find the zeros of r^2-8r=0
The zeros of r^2-8r=0 are r=8,r=0