What are the solutions to the equation x^2-4x=60 ?

The solutions to the equation x^2-4x=60 are x=10,x=-6

Find the zeros of x^2-4x=60

The zeros of x^2-4x=60 are x=10,x=-6

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x^{2} - 4 x = 60

x = 10, x = - 6

Solution steps

x^{2} - 4 x = 60

Move

60

to the left side

x^{2} - 4 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 60) = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 1}

x = \frac{- ( - 4 ) + 16}{2 \cdot 1} : 10

x = \frac{- ( - 4 ) - 16}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 10, x = - 6

5 n - 11 < - 4.4 + 2 n

\frac{5 a ^{2} - 9 a - 2}{a ^{2} + 4 a - 12}

\frac{304 + 2 x}{6} \geq 70

(\frac{5}{9})^{- 1}

- \frac{32}{4 ^{3}} + \frac{4}{4 ^{2}}

What are the solutions to the equation x^2-4x=60 ?
The solutions to the equation x^2-4x=60 are x=10,x=-6
Find the zeros of x^2-4x=60
The zeros of x^2-4x=60 are x=10,x=-6