What are the solutions to the equation 2x^2-5x-33=0 ?

The solutions to the equation 2x^2-5x-33=0 are x= 11/2 ,x=-3

Find the zeros of 2x^2-5x-33=0

The zeros of 2x^2-5x-33=0 are x= 11/2 ,x=-3

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2 x^{2} - 5 x - 33 = 0

x = \frac{11}{2}, x = - 3

Decimal Notation

x = 5.5, x = - 3

Solution steps

2 x^{2} - 5 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 33 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 33) = 17

x_{1, 2} = \frac{- ( - 5 ) \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 17}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 17}{2 \cdot 2}

x = \frac{- ( - 5 ) + 17}{2 \cdot 2} : \frac{11}{2}

x = \frac{- ( - 5 ) - 17}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{11}{2}, x = - 3

2 a^{2} b^{2} - 2 a^{2} - 2 a b^{3} + 2 ab

\frac{2}{3} (25)^{\frac{3}{2}}

4 x + 3 x^{2} - 5 = 0

5 (x + 1) - 6 (x - 3) + 2 (2 x + 1) = 28

2 \cdot \frac{12}{13} \cdot \frac{5}{13}

What are the solutions to the equation 2x^2-5x-33=0 ?
The solutions to the equation 2x^2-5x-33=0 are x= 11/2 ,x=-3
Find the zeros of 2x^2-5x-33=0
The zeros of 2x^2-5x-33=0 are x= 11/2 ,x=-3