What are the solutions to the equation 12x^2-16=0 ?

The solutions to the equation 12x^2-16=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

Find the zeros of 12x^2-16=0

The zeros of 12x^2-16=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

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12 x^{2} - 16 = 0

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 1.15470 \dots, x = - 1.15470 \dots

Solution steps

12 x^{2} - 16 = 0

Move

16

to the right side

12 x^{2} = 16

Divide both sides by

12

x^{2} = \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{3}, x = - \frac{4}{3}

\frac{4}{3} = \frac{2}{3}

- \frac{4}{3} = - \frac{2}{3}

x = \frac{2}{3}, x = - \frac{2}{3}

- 2 (\frac{1}{2})^{1}

\frac{12 x + 3}{3} + 10 \geq 3

a^{3} + 4 a^{2} + a + 4

i^{83}

7 (t + 8) = 8 t

What are the solutions to the equation 12x^2-16=0 ?
The solutions to the equation 12x^2-16=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))
Find the zeros of 12x^2-16=0
The zeros of 12x^2-16=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))