What are the solutions to the equation 4x^2-1=-8x ?

The solutions to the equation 4x^2-1=-8x are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2

Find the zeros of 4x^2-1=-8x

The zeros of 4x^2-1=-8x are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 1 = - 8 x

x = \frac{- 2 + 5}{2}, x = - \frac{2 + 5}{2}

Decimal Notation

x = 0.11803 \dots, x = - 2.11803 \dots

Solution steps

4 x^{2} - 1 = - 8 x

Move

8 x

to the left side

4 x^{2} - 1 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 1) = 45

x_{1, 2} = \frac{- 8 \pm 4 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 5}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 5}{2 \cdot 4}

x = \frac{- 8 + 4 5}{2 \cdot 4} : \frac{- 2 + 5}{2}

x = \frac{- 8 - 4 5}{2 \cdot 4} : - \frac{2 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 5}{2}, x = - \frac{2 + 5}{2}

4 w^{3} + 7 w^{2} + 12 w + 21

2 \cdot 2^{n}

\frac{8}{12} (2 x - 1) + \frac{3}{4} (x + 1) = 3

16 x^{2} + 18 x + 5

6 x + 5 = 8 x + 11

What are the solutions to the equation 4x^2-1=-8x ?
The solutions to the equation 4x^2-1=-8x are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2
Find the zeros of 4x^2-1=-8x
The zeros of 4x^2-1=-8x are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2