What are the solutions to the equation 3(x-1)(x+2)=0 ?

The solutions to the equation 3(x-1)(x+2)=0 are x=1,x=-2

Find the zeros of 3(x-1)(x+2)=0

The zeros of 3(x-1)(x+2)=0 are x=1,x=-2

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3 (x - 1) (x + 2) = 0

x = 1, x = - 2

Solution steps

3 (x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

4 x^{2} + 10 x + 13 = 0

1 - 3 x + 1 \leq 2 - 2 x - x

- x^{4} + 4 x^{2}

6 x^{2} + 8 x + 1 = 0

x^{2} - 11 x + 18 > 0

What are the solutions to the equation 3(x-1)(x+2)=0 ?
The solutions to the equation 3(x-1)(x+2)=0 are x=1,x=-2
Find the zeros of 3(x-1)(x+2)=0
The zeros of 3(x-1)(x+2)=0 are x=1,x=-2