What are the solutions to the equation 3t-4.9t^2=0 ?

The solutions to the equation 3t-4.9t^2=0 are t=0,t= 30/49

Find the zeros of 3t-4.9t^2=0

The zeros of 3t-4.9t^2=0 are t=0,t= 30/49

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 t - 4.9 t^{2} = 0

t = 0, t = \frac{30}{49}

Decimal Notation

t = 0, t = 0.61224 \dots

Solution steps

3 t - 4.9 t^{2} = 0

Multiply both sides by

10

30 t - 49 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 49 t^{2} + 30 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 49 ) \cdot 0}{2 ( - 49 )}

3 0^{2} - 4 (- 49) \cdot 0 = 30

t_{1, 2} = \frac{- 30 \pm 30}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 30 + 30}{2 ( - 49 )}, t_{2} = \frac{- 30 - 30}{2 ( - 49 )}

t = \frac{- 30 + 30}{2 ( - 49 )} : 0

t = \frac{- 30 - 30}{2 ( - 49 )} : \frac{30}{49}

The solutions to the quadratic equation are:

t = 0, t = \frac{30}{49}

25 z^{2} + 223 = 150 z

x^{2} - 10 x + 32 = 0

- 30 n = - 27 n - 63

- 4 x = 20

- 4 ∣ 3 x - 1 ∣ = - 16

What are the solutions to the equation 3t-4.9t^2=0 ?
The solutions to the equation 3t-4.9t^2=0 are t=0,t= 30/49
Find the zeros of 3t-4.9t^2=0
The zeros of 3t-4.9t^2=0 are t=0,t= 30/49