What are the solutions to the equation 2x(x+5)=5 ?

The solutions to the equation 2x(x+5)=5 are x=(-5+sqrt(35))/2 ,x=-(5+sqrt(35))/2

Find the zeros of 2x(x+5)=5

The zeros of 2x(x+5)=5 are x=(-5+sqrt(35))/2 ,x=-(5+sqrt(35))/2

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2 x (x + 5) = 5

x = \frac{- 5 + 35}{2}, x = - \frac{5 + 35}{2}

Decimal Notation

x = 0.45803 \dots, x = - 5.45803 \dots

Solution steps

2 x (x + 5) = 5

Expand

2 x (x + 5) : 2 x^{2} + 10 x

2 x^{2} + 10 x = 5

Move

5

to the left side

2 x^{2} + 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 5) = 235

x_{1, 2} = \frac{- 10 \pm 2 35}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 2 35}{2 \cdot 2}, x_{2} = \frac{- 10 - 2 35}{2 \cdot 2}

x = \frac{- 10 + 2 35}{2 \cdot 2} : \frac{- 5 + 35}{2}

x = \frac{- 10 - 2 35}{2 \cdot 2} : - \frac{5 + 35}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 35}{2}, x = - \frac{5 + 35}{2}

x^{1} \cdot x^{\frac{1}{2}}

\frac{d}{1.9} = 2.05

5 x^{2} = 240

175 - 7 k^{2}

9 - 10

What are the solutions to the equation 2x(x+5)=5 ?
The solutions to the equation 2x(x+5)=5 are x=(-5+sqrt(35))/2 ,x=-(5+sqrt(35))/2
Find the zeros of 2x(x+5)=5
The zeros of 2x(x+5)=5 are x=(-5+sqrt(35))/2 ,x=-(5+sqrt(35))/2