What are the solutions to the equation 2x^2+3x-9=x-5 ?

The solutions to the equation 2x^2+3x-9=x-5 are x=1,x=-2

Find the zeros of 2x^2+3x-9=x-5

The zeros of 2x^2+3x-9=x-5 are x=1,x=-2

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2 x^{2} + 3 x - 9 = x - 5

x = 1, x = - 2

Solution steps

2 x^{2} + 3 x - 9 = x - 5

Move

5

to the left side

2 x^{2} + 3 x - 4 = x

Move

x

to the left side

2 x^{2} + 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 4) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 2}, x_{2} = \frac{- 2 - 6}{2 \cdot 2}

x = \frac{- 2 + 6}{2 \cdot 2} : 1

x = \frac{- 2 - 6}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

3 n^{2} + 6 n - 24

30 + \frac{5 \cdot 1 0 ^{- 7}}{4 \cdot 1 0 ^{- 9}}

4 + 2 (a + 5) < - 2 (- a - 4)

\frac{( 201 8 ^{2018} )}{20}

\frac{- 8 + r}{2} > - 8

What are the solutions to the equation 2x^2+3x-9=x-5 ?
The solutions to the equation 2x^2+3x-9=x-5 are x=1,x=-2
Find the zeros of 2x^2+3x-9=x-5
The zeros of 2x^2+3x-9=x-5 are x=1,x=-2