What is the answer to |x^2-4x+3|=x-2 ?

The answer to |x^2-4x+3|=x-2 is x=(3+sqrt(5))/2 \lor x=(5+sqrt(5))/2

Solve for x: |x^2-4x+3|=x-2

The solution is x=(3+sqrt(5))/2 \lor x=(5+sqrt(5))/2

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x^{2} - 4 x + 3 = x - 2

x = \frac{3 + 5}{2} or x = \frac{5 + 5}{2}

Decimal Notation

x = 2.61803 \dots, x = 3.61803 \dots

Solution steps

x^{2} - 4 x + 3 = x - 2

Find positive and negative intervals

x \leq 1, 1 < x < 3, x \geq 3

Solve the inequality for each interval

No Solution or x = \frac{3 + 5}{2} or x = \frac{5 + 5}{2}

x = \frac{3 + 5}{2} or x = \frac{5 + 5}{2}

x^{2} - x - 6 \leq 0

6 x - 3 = 4 x - 3 - 2 x

- 4 x^{0} z^{3} \cdot 3 y

\frac{m}{- 6} + 16 \geq 19

\frac{4 ( 3 x + 6 )}{5} + 3 = \frac{2 ( 2 x + 5 )}{3} - 3 x

What is the answer to |x^2-4x+3|=x-2 ?
The answer to |x^2-4x+3|=x-2 is x=(3+sqrt(5))/2 \lor x=(5+sqrt(5))/2
Solve for x: |x^2-4x+3|=x-2
The solution is x=(3+sqrt(5))/2 \lor x=(5+sqrt(5))/2