What are the solutions to the equation x^2-6x+36=0 ?

The solutions to the equation x^2-6x+36=0 are x=3+3sqrt(3)i,x=3-3sqrt(3)i

Find the zeros of x^2-6x+36=0

The zeros of x^2-6x+36=0 are x=3+3sqrt(3)i,x=3-3sqrt(3)i

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x^{2} - 6 x + 36 = 0

x = 3 + 33 i, x = 3 - 33 i

Solution steps

x^{2} - 6 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 36 : 63 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6 3 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6 3 i}{2 \cdot 1} : 3 + 33 i

x = \frac{- ( - 6 ) - 6 3 i}{2 \cdot 1} : 3 - 33 i

The solutions to the quadratic equation are:

x = 3 + 33 i, x = 3 - 33 i

3 x + 4 = 6

12 x y^{5} + 60 x^{4} y^{2} - 24 x^{3} y^{3}

\frac{5}{3} x + \frac{3}{4} < \frac{2}{5}

e^{- \frac{x ^{2}}{2}}

2^{27}

What are the solutions to the equation x^2-6x+36=0 ?
The solutions to the equation x^2-6x+36=0 are x=3+3sqrt(3)i,x=3-3sqrt(3)i
Find the zeros of x^2-6x+36=0
The zeros of x^2-6x+36=0 are x=3+3sqrt(3)i,x=3-3sqrt(3)i