What are the solutions to the equation 120=(x-14)(x-6)0.5 ?

The solutions to the equation 120=(x-14)(x-6)0.5 are x=26,x=-6

Find the zeros of 120=(x-14)(x-6)0.5

The zeros of 120=(x-14)(x-6)0.5 are x=26,x=-6

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120 = (x - 14) (x - 6) 0.5

x = 26, x = - 6

Solution steps

120 = (x - 14) (x - 6) \cdot 0.5

Multiply both sides by

10

1200 = 5 (x - 14) (x - 6)

Expand

5 (x - 14) (x - 6) : 5 x^{2} - 100 x + 420

1200 = 5 x^{2} - 100 x + 420

Switch sides

5 x^{2} - 100 x + 420 = 1200

Move

1200

to the left side

5 x^{2} - 100 x - 780 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 100 ) \pm ( - 100 ) ^{2} - 4 \cdot 5 ( - 780 )}{2 \cdot 5}

(- 100)^{2} - 4 \cdot 5 (- 780) = 160

x_{1, 2} = \frac{- ( - 100 ) \pm 160}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 100 ) + 160}{2 \cdot 5}, x_{2} = \frac{- ( - 100 ) - 160}{2 \cdot 5}

x = \frac{- ( - 100 ) + 160}{2 \cdot 5} : 26

x = \frac{- ( - 100 ) - 160}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = 26, x = - 6

4.9 x^{2} - 10 x - 14.1 = 0

55 + 78 + 74 + (45 + z) + z = 360

(x - 4)^{2} = 23

\frac{a}{2} > 4

What are the solutions to the equation 120=(x-14)(x-6)0.5 ?
The solutions to the equation 120=(x-14)(x-6)0.5 are x=26,x=-6
Find the zeros of 120=(x-14)(x-6)0.5
The zeros of 120=(x-14)(x-6)0.5 are x=26,x=-6