What are the solutions to the equation 2x^2+9x-3=0 ?

The solutions to the equation 2x^2+9x-3=0 are x=(-9+sqrt(105))/4 ,x=(-9-sqrt(105))/4

Find the zeros of 2x^2+9x-3=0

The zeros of 2x^2+9x-3=0 are x=(-9+sqrt(105))/4 ,x=(-9-sqrt(105))/4

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2 x^{2} + 9 x - 3 = 0

x = \frac{- 9 + 105}{4}, x = \frac{- 9 - 105}{4}

Decimal Notation

x = 0.31173 \dots, x = - 4.81173 \dots

Solution steps

2 x^{2} + 9 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 3) = 105

x_{1, 2} = \frac{- 9 \pm 105}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 105}{2 \cdot 2}, x_{2} = \frac{- 9 - 105}{2 \cdot 2}

x = \frac{- 9 + 105}{2 \cdot 2} : \frac{- 9 + 105}{4}

x = \frac{- 9 - 105}{2 \cdot 2} : \frac{- 9 - 105}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 105}{4}, x = \frac{- 9 - 105}{4}

- 2 x^{2} - 12 x - 10

4 m^{2} + 4 m + 1

\frac{a ^{2} - 1}{a ^{2} + 2 a - 3}

3 [4 x + 7 (2 - 2 x)]

4 x^{2} = 5 x + 21

What are the solutions to the equation 2x^2+9x-3=0 ?
The solutions to the equation 2x^2+9x-3=0 are x=(-9+sqrt(105))/4 ,x=(-9-sqrt(105))/4
Find the zeros of 2x^2+9x-3=0
The zeros of 2x^2+9x-3=0 are x=(-9+sqrt(105))/4 ,x=(-9-sqrt(105))/4