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Popular >

2x^2+12x>= 4x-8

Solution

2 x^{2} + 12 x \geq 4 x - 8

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

2 x^{2} + 12 x \geq 4 x - 8

Rewrite in standard form

x^{2} + 4 x + 4 \geq 0

Factor

x^{2} + 4 x + 4 : (x + 2)^{2}

(x + 2)^{2} \geq 0

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

\frac{3 x - 1}{5} = 10

3/8 (x+8)= 1/2 (x+5)+1/4

\frac{3}{8} (x + 8) = \frac{1}{2} (x + 5) + \frac{1}{4}

simplify 2(1+3i)-3/2 (-2+i)simplify

2 (1 + 3 i) - \frac{3}{2} (- 2 + i)

2(2x-1/2)= 1/7 (1-x/2)

2 (2 x - \frac{1}{2}) = \frac{1}{7} (1 - \frac{x}{2})

simplify pi(12)^2 simplify

π (12)^{2}

Frequently Asked Questions (FAQ)

What is 2x^2+12x>= 4x-8 ?
The solution to 2x^2+12x>= 4x-8 is True for all x