What are the solutions to the equation 4k^2-12k+5=0 ?

The solutions to the equation 4k^2-12k+5=0 are k= 5/2 ,k= 1/2

Find the zeros of 4k^2-12k+5=0

The zeros of 4k^2-12k+5=0 are k= 5/2 ,k= 1/2

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4 k^{2} - 12 k + 5 = 0

k = \frac{5}{2}, k = \frac{1}{2}

Decimal Notation

k = 2.5, k = 0.5

Solution steps

4 k^{2} - 12 k + 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 5 = 8

k_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 4}, k_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 4}

k = \frac{- ( - 12 ) + 8}{2 \cdot 4} : \frac{5}{2}

k = \frac{- ( - 12 ) - 8}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

k = \frac{5}{2}, k = \frac{1}{2}

\frac{x + 6}{2} = - 7

4 x + 8

\frac{3 x}{x - 8} < 1

40 y^{5} + 5 y^{2}

\frac{1}{2 - 3} \frac{1}{2 + 3}

What are the solutions to the equation 4k^2-12k+5=0 ?
The solutions to the equation 4k^2-12k+5=0 are k= 5/2 ,k= 1/2
Find the zeros of 4k^2-12k+5=0
The zeros of 4k^2-12k+5=0 are k= 5/2 ,k= 1/2