What are the solutions to the equation 3a^2+2a-1=0 ?

The solutions to the equation 3a^2+2a-1=0 are a= 1/3 ,a=-1

Find the zeros of 3a^2+2a-1=0

The zeros of 3a^2+2a-1=0 are a= 1/3 ,a=-1

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3 a^{2} + 2 a - 1 = 0

a = \frac{1}{3}, a = - 1

Decimal Notation

a = 0.33333 \dots, a = - 1

Solution steps

3 a^{2} + 2 a - 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 1) = 4

a_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- 2 + 4}{2 \cdot 3}, a_{2} = \frac{- 2 - 4}{2 \cdot 3}

a = \frac{- 2 + 4}{2 \cdot 3} : \frac{1}{3}

a = \frac{- 2 - 4}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

a = \frac{1}{3}, a = - 1

2 d + 2 < 6

m^{2} - m - 56

x^{3} - x^{2} - 6 x < 0

\frac{3}{8} \cdot \frac{2}{3}

2 lo g_{5} (3) - lo g_{5} (45)

What are the solutions to the equation 3a^2+2a-1=0 ?
The solutions to the equation 3a^2+2a-1=0 are a= 1/3 ,a=-1
Find the zeros of 3a^2+2a-1=0
The zeros of 3a^2+2a-1=0 are a= 1/3 ,a=-1