What are the solutions to the equation -3x^2+60x-121=0 ?

The solutions to the equation -3x^2+60x-121=0 are x=(30-sqrt(537))/3 ,x=(30+sqrt(537))/3

Find the zeros of -3x^2+60x-121=0

The zeros of -3x^2+60x-121=0 are x=(30-sqrt(537))/3 ,x=(30+sqrt(537))/3

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- 3 x^{2} + 60 x - 121 = 0

x = \frac{30 - 537}{3}, x = \frac{30 + 537}{3}

Decimal Notation

x = 2.27557 \dots, x = 17.72442 \dots

Solution steps

- 3 x^{2} + 60 x - 121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 3 ) ( - 121 )}{2 ( - 3 )}

6 0^{2} - 4 (- 3) (- 121) = 2537

x_{1, 2} = \frac{- 60 \pm 2 537}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 60 + 2 537}{2 ( - 3 )}, x_{2} = \frac{- 60 - 2 537}{2 ( - 3 )}

x = \frac{- 60 + 2 537}{2 ( - 3 )} : \frac{30 - 537}{3}

x = \frac{- 60 - 2 537}{2 ( - 3 )} : \frac{30 + 537}{3}

The solutions to the quadratic equation are:

x = \frac{30 - 537}{3}, x = \frac{30 + 537}{3}

3 h = 7 (72 - 73 h) - 10

- x = 2

\frac{7}{12} + \frac{8}{6} - \frac{9}{3}

5 - 9

x - 1 \leq 4 x + 5 < 6 x + 7

What are the solutions to the equation -3x^2+60x-121=0 ?
The solutions to the equation -3x^2+60x-121=0 are x=(30-sqrt(537))/3 ,x=(30+sqrt(537))/3
Find the zeros of -3x^2+60x-121=0
The zeros of -3x^2+60x-121=0 are x=(30-sqrt(537))/3 ,x=(30+sqrt(537))/3