What are the solutions to the equation x^2+5x+(5/2)^2=0 ?

The solutions to the equation x^2+5x+(5/2)^2=0 are x=-2.5

Find the zeros of x^2+5x+(5/2)^2=0

The zeros of x^2+5x+(5/2)^2=0 are x=-2.5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 5 x + (\frac{5}{2})^{2} = 0

x = - 2.5

Solution steps

x^{2} + 5 x + (\frac{5}{2})^{2} = 0

Expand

x^{2} + 5 x + (\frac{5}{2})^{2} : x^{2} + 5 x + \frac{25}{4}

x^{2} + 5 x + \frac{25}{4} = 0

Factor

x^{2} + 5 x + \frac{25}{4} : (x + 2.5)^{2}

(x + 2.5)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2.5 = 0

Solve

x + 2.5 = 0 : x = - 2.5

The solution to the quadratic equation is:

x = - 2.5

v p + 12 v + 8 p + 96

\frac{3}{2} 6

4 (x + 3) < 3 x + 7

5 - 2

What are the solutions to the equation x^2+5x+(5/2)^2=0 ?
The solutions to the equation x^2+5x+(5/2)^2=0 are x=-2.5
Find the zeros of x^2+5x+(5/2)^2=0
The zeros of x^2+5x+(5/2)^2=0 are x=-2.5