What is the answer to 5x-((2x)/3+x/2)= 1/3 (9x-1/2) ?

The answer to 5x-((2x)/3+x/2)= 1/3 (9x-1/2) is x=-1/5

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5x-((2x)/3+x/2)= 1/3 (9x-1/2)

5 x - (\frac{2 x}{3} + \frac{x}{2}) = \frac{1}{3} (9 x - \frac{1}{2})

x = - \frac{1}{5}

Decimal Notation

x = - 0.2

Solution steps

5 x - (\frac{2 x}{3} + \frac{x}{2}) = \frac{1}{3} (9 x - \frac{1}{2})

Expand

5 x - (\frac{2 x}{3} + \frac{x}{2}) : \frac{23 x}{6}

Expand

\frac{1}{3} (9 x - \frac{1}{2}) : 3 x - \frac{1}{6}

\frac{23 x}{6} = 3 x - \frac{1}{6}

Multiply both sides by

6

23 x = 18 x - 1

Move

18 x

to the left side

5 x = - 1

Divide both sides by

5

x = - \frac{1}{5}

9 x^{2} + 18 x - 7

3 x^{2} = - 9 x

c^{2} + 7 c + 12 = 0

(\frac{5}{b})^{- 3}

1 2^{l o g_{12} (144)}

What is the answer to 5x-((2x)/3+x/2)= 1/3 (9x-1/2) ?
The answer to 5x-((2x)/3+x/2)= 1/3 (9x-1/2) is x=-1/5
Solve for x: 5x-((2x)/3+x/2)= 1/3 (9x-1/2)
The solution is x=-1/5