What is factor b^2-b-20 ?

The solution to factor b^2-b-20 is (b+4)(b-5)

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factor b^2-b-20

factor

b^{2} - b - 20

(b + 4) (b - 5)

Solution steps

b^{2} - b - 20

Break the expression into groups

= (b^{2} + 4 b) + (- 5 b - 20)

Factor out

b

from

b^{2} + 4 b : b (b + 4)

Factor out

- 5

from

- 5 b - 20 : - 5 (b + 4)

= b (b + 4) - 5 (b + 4)

Factor out common term

b + 4

= (b + 4) (b - 5)

2 x^{4} + 16 x y^{3}

- ∣ 2 x + 6 ∣ = 1

(2 g h^{4})^{3} [(- 2 g^{4} h)^{3}]^{2}

\frac{3}{20} - \frac{3}{30}

\frac{3}{2 + 3} + \frac{2}{3}