What are the solutions to the equation x^2+2x+8=0 ?

The solutions to the equation x^2+2x+8=0 are x=-1+sqrt(7)i,x=-1-sqrt(7)i

Find the zeros of x^2+2x+8=0

The zeros of x^2+2x+8=0 are x=-1+sqrt(7)i,x=-1-sqrt(7)i

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x^{2} + 2 x + 8 = 0

x = - 1 + 7 i, x = - 1 - 7 i

Solution steps

x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 8 : 27 i

x_{1, 2} = \frac{- 2 \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 7 i}{2 \cdot 1}

x = \frac{- 2 + 2 7 i}{2 \cdot 1} : - 1 + 7 i

x = \frac{- 2 - 2 7 i}{2 \cdot 1} : - 1 - 7 i

The solutions to the quadratic equation are:

x = - 1 + 7 i, x = - 1 - 7 i

3 (x + 9) = 6 (x + 1)

64 - 6 y \geq 1 - y

4.18 = 2.2 g

9 - 13 t \geq - 47 - 5 t

- 2.65 - 16.3

What are the solutions to the equation x^2+2x+8=0 ?
The solutions to the equation x^2+2x+8=0 are x=-1+sqrt(7)i,x=-1-sqrt(7)i
Find the zeros of x^2+2x+8=0
The zeros of x^2+2x+8=0 are x=-1+sqrt(7)i,x=-1-sqrt(7)i