What are the solutions to the equation x^2-2sqrt(6)x+5=0 ?

The solutions to the equation x^2-2sqrt(6)x+5=0 are x=sqrt(6)+1,x=sqrt(6)-1

Find the zeros of x^2-2sqrt(6)x+5=0

The zeros of x^2-2sqrt(6)x+5=0 are x=sqrt(6)+1,x=sqrt(6)-1

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x^{2} - 26 x + 5 = 0

x = 6 + 1, x = 6 - 1

Decimal Notation

x = 3.44948 \dots, x = 1.44948 \dots

Solution steps

x^{2} - 26 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 6 ) \pm ( - 2 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 26)^{2} - 4 \cdot 1 \cdot 5 = 2

x_{1, 2} = \frac{- ( - 2 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 6 ) + 2}{2 \cdot 1} : 6 + 1

x = \frac{- ( - 2 6 ) - 2}{2 \cdot 1} : 6 - 1

The solutions to the quadratic equation are:

x = 6 + 1, x = 6 - 1

\frac{4}{4 ^{- 2}}

6 \cdot 3 = (x \cdot 5) - (x \cdot 2)

\frac{4}{3 x} + \frac{8}{x ^{3}} + \frac{2}{5 x y}

\frac{2 x + 7}{- 3} \leq x - 9

1 \times (- 4) - 8 \times \frac{9}{- 3}

What are the solutions to the equation x^2-2sqrt(6)x+5=0 ?
The solutions to the equation x^2-2sqrt(6)x+5=0 are x=sqrt(6)+1,x=sqrt(6)-1
Find the zeros of x^2-2sqrt(6)x+5=0
The zeros of x^2-2sqrt(6)x+5=0 are x=sqrt(6)+1,x=sqrt(6)-1