What are the solutions to the equation 7x^2-14x+7=0 ?

The solutions to the equation 7x^2-14x+7=0 are x=1

Find the zeros of 7x^2-14x+7=0

The zeros of 7x^2-14x+7=0 are x=1

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7 x^{2} - 14 x + 7 = 0

x = 1

Solution steps

7 x^{2} - 14 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 7 \cdot 7}{2 \cdot 7}

(- 14)^{2} - 4 \cdot 7 \cdot 7 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 7}

x = \frac{- ( - 14 )}{2 \cdot 7}

\frac{- ( - 14 )}{2 \cdot 7} = 1

x = 1

The solution to the quadratic equation is:

x = 1

81 - 3 m^{3}

32 t - 16 t^{2} = 0

\frac{4}{5} - \frac{3}{10}

\frac{0}{9}

2 ∣ 4 x ∣ = 16

What are the solutions to the equation 7x^2-14x+7=0 ?
The solutions to the equation 7x^2-14x+7=0 are x=1
Find the zeros of 7x^2-14x+7=0
The zeros of 7x^2-14x+7=0 are x=1