What are the solutions to the equation 25x^2-20x-2=-6 ?

The solutions to the equation 25x^2-20x-2=-6 are x= 2/5

Find the zeros of 25x^2-20x-2=-6

The zeros of 25x^2-20x-2=-6 are x= 2/5

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25 x^{2} - 20 x - 2 = - 6

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

25 x^{2} - 20 x - 2 = - 6

Move

6

to the left side

25 x^{2} - 20 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 20 )}{2 \cdot 25}

\frac{- ( - 20 )}{2 \cdot 25} = \frac{2}{5}

x = \frac{2}{5}

The solution to the quadratic equation is:

x = \frac{2}{5}

x^{2} - 7 \leq 0

0 = - 16 t^{2} + 128 t

x - 6 - 10 - x \geq 1

2 x^{2} - 13 x - 2 = 0

8 - 4 (2 - x) \leq - 2 x

What are the solutions to the equation 25x^2-20x-2=-6 ?
The solutions to the equation 25x^2-20x-2=-6 are x= 2/5
Find the zeros of 25x^2-20x-2=-6
The zeros of 25x^2-20x-2=-6 are x= 2/5