What is the answer to 4(u+1)-7=3(u-1)+u ?

The answer to 4(u+1)-7=3(u-1)+u is True for all u

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4(u+1)-7=3(u-1)+u

4 (u + 1) - 7 = 3 (u - 1) + u

True for all u

Solution steps

4 (u + 1) - 7 = 3 (u - 1) + u

Expand

4 (u + 1) - 7 : 4 u - 3

Expand

3 (u - 1) + u : 4 u - 3

4 u - 3 = 4 u - 3

Move

3

to the right side

4 u = 4 u

Move

4 u

to the left side

0 = 0

Both sides are equal

True for all u

1 + 64 y^{3}

4 x^{3} - 64 x

\frac{1}{3} u^{2} + \frac{2}{3} u = - \frac{1}{12}

(5 - 4 i)^{2}

\frac{3 x + 2}{x ^{3} - x ^{2}} > 0

What is the answer to 4(u+1)-7=3(u-1)+u ?
The answer to 4(u+1)-7=3(u-1)+u is True for all u
Solve for u: 4(u+1)-7=3(u-1)+u
The solution is True for all u